What are the solutions to the equation 4.328=541(1+y/4)^{15} ?

The solutions to the equation 4.328=541(1+y/4)^{15} are y=-1.10088…

Find the zeros of 4.328=541(1+y/4)^{15}

The zeros of 4.328=541(1+y/4)^{15} are y=-1.10088…

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4.328 = 541 (1 + \frac{y}{4})^{15}

y = - 1.10088 \dots

Solution steps

4.328 = 541 (1 + \frac{y}{4})^{15}

Switch sides

541 (1 + \frac{y}{4})^{15} = 4.328

Divide both sides by

541

(1 + \frac{y}{4})^{15} = 0.008

For

(g (x))^{n} = f (a)

, n is odd, the solution is

Solve

The solution is

y = - 1.10088 \dots

x^{4} - 5 x^{3} + x^{2} - 2 x - 15 = 0

x^{3} = 9 x^{2} - 20 x

(3 x - 8) (x + 2) = 2 x^{3}

x^{3} - 6 x - 9 = 0

3 x^{5} - 20 x^{3} + 16 = 0

What are the solutions to the equation 4.328=541(1+y/4)^{15} ?
The solutions to the equation 4.328=541(1+y/4)^{15} are y=-1.10088…
Find the zeros of 4.328=541(1+y/4)^{15}
The zeros of 4.328=541(1+y/4)^{15} are y=-1.10088…