What are the solutions to the equation x^3+4x^2-6=0 ?

The solutions to the equation x^3+4x^2-6=0 are x\approx 1.08613…,x\approx-1.57199…,x\approx-3.51413…

Find the zeros of x^3+4x^2-6=0

The zeros of x^3+4x^2-6=0 are x\approx 1.08613…,x\approx-1.57199…,x\approx-3.51413…

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x^{3} + 4 x^{2} - 6 = 0

x \approx 1.08613 \dots, x \approx - 1.57199 \dots, x \approx - 3.51413 \dots

Solution steps

x^{3} + 4 x^{2} - 6 = 0

Find one solution for

x^{3} + 4 x^{2} - 6 = 0

using Newton-Raphson:

x \approx 1.08613 \dots

Apply long division:

\frac{x ^{3} + 4 x ^{2} - 6}{x - 1.08613 \dots} = x^{2} + 5.08613 \dots x + 5.52419 \dots

x^{2} + 5.08613 \dots x + 5.52419 \dots \approx 0

Find one solution for

x^{2} + 5.08613 \dots x + 5.52419 \dots = 0

using Newton-Raphson:

x \approx - 1.57199 \dots

Apply long division:

\frac{x ^{2} + 5.08613 \dots x + 5.52419 \dots}{x + 1.57199 \dots} = x + 3.51413 \dots

x + 3.51413 \dots \approx 0

x \approx - 3.51413 \dots

The solutions are

x \approx 1.08613 \dots, x \approx - 1.57199 \dots, x \approx - 3.51413 \dots

3 x^{4} - 7 x^{2} - 6 = 0

4 x^{2} 8 x - 7 = 0

3 x^{3} + 12 x = 5 x^{2} + 20

b^{4} = 16.6

(x + 1) (x^{2} - 4) = 0

What are the solutions to the equation x^3+4x^2-6=0 ?
The solutions to the equation x^3+4x^2-6=0 are x\approx 1.08613…,x\approx-1.57199…,x\approx-3.51413…
Find the zeros of x^3+4x^2-6=0
The zeros of x^3+4x^2-6=0 are x\approx 1.08613…,x\approx-1.57199…,x\approx-3.51413…