What are the solutions to the equation 2x^3+x^2+18x+9=0 ?

The solutions to the equation 2x^3+x^2+18x+9=0 are x=-1/2 ,x=3i,x=-3i

Find the zeros of 2x^3+x^2+18x+9=0

The zeros of 2x^3+x^2+18x+9=0 are x=-1/2 ,x=3i,x=-3i

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2 x^{3} + x^{2} + 18 x + 9 = 0

x = - \frac{1}{2}, x = 3 i, x = - 3 i

Solution steps

2 x^{3} + x^{2} + 18 x + 9 = 0

Factor

2 x^{3} + x^{2} + 18 x + 9 : (2 x + 1) (x^{2} + 9)

(2 x + 1) (x^{2} + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 1 = 0 or x^{2} + 9 = 0

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

x^{2} + 9 = 0 : x = 3 i, x = - 3 i

The solutions are

x = - \frac{1}{2}, x = 3 i, x = - 3 i

64 a^{6} - 112 a^{4} + 56 a^{2} - 7 = 0

4 x^{2} + 8 x^{4} = (x^{2} + 2 x + 1)

4 x^{3} - 27 x^{2} - 11 x - 1 = 0

(1 - m)^{3} = \frac{1}{3}

x^{1} + 2 x^{2} + x^{3} = - 1

What are the solutions to the equation 2x^3+x^2+18x+9=0 ?
The solutions to the equation 2x^3+x^2+18x+9=0 are x=-1/2 ,x=3i,x=-3i
Find the zeros of 2x^3+x^2+18x+9=0
The zeros of 2x^3+x^2+18x+9=0 are x=-1/2 ,x=3i,x=-3i