What are the solutions to the equation 1305=2267*(1+X)^6 ?

The solutions to the equation 1305=2267*(1+X)^6 are X=\sqrt[6]{1305/2267}-1,X=-\sqrt[6]{1305/2267}-1

Find the zeros of 1305=2267*(1+X)^6

The zeros of 1305=2267*(1+X)^6 are X=\sqrt[6]{1305/2267}-1,X=-\sqrt[6]{1305/2267}-1

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1305 = 2267 \cdot (1 + X)^{6}

Decimal Notation

X = - 0.08793 \dots, X = - 1.91206 \dots

Solution steps

1305 = 2267 (1 + X)^{6}

Switch sides

2267 (1 + X)^{6} = 1305

Divide both sides by

2267

(1 + X)^{6} = \frac{1305}{2267}

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

z^{3} = 4 - 43 + 0 i

12 = \frac{1}{2} a^{21} a

x^{3} - 3 x^{2} + 9 x + 13 = 0

x^{8} + 35 x^{4} = 36

x (3 x^{2} - 2 x - 12 x + 8) = 0

What are the solutions to the equation 1305=2267*(1+X)^6 ?
The solutions to the equation 1305=2267*(1+X)^6 are X=\sqrt[6]{1305/2267}-1,X=-\sqrt[6]{1305/2267}-1
Find the zeros of 1305=2267*(1+X)^6
The zeros of 1305=2267*(1+X)^6 are X=\sqrt[6]{1305/2267}-1,X=-\sqrt[6]{1305/2267}-1