What are the solutions to the equation 2x^3+7x^2-4x=0 ?

The solutions to the equation 2x^3+7x^2-4x=0 are x=0,x= 1/2 ,x=-4

Find the zeros of 2x^3+7x^2-4x=0

The zeros of 2x^3+7x^2-4x=0 are x=0,x= 1/2 ,x=-4

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2 x^{3} + 7 x^{2} - 4 x = 0

x = 0, x = \frac{1}{2}, x = - 4

Decimal Notation

x = 0, x = 0.5, x = - 4

Solution steps

2 x^{3} + 7 x^{2} - 4 x = 0

Factor

2 x^{3} + 7 x^{2} - 4 x : x (2 x - 1) (x + 4)

x (2 x - 1) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x - 1 = 0 or x + 4 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

x + 4 = 0 : x = - 4

The solutions are

x = 0, x = \frac{1}{2}, x = - 4

x^{3} + 5 x^{2} + 8 x + 3 = 0

x, 9 x^{4} + 6 y^{3} = 8

x^{2} (x - 1) (2 x + 7) = 0

16 x^{4} - 4 5^{3} + 9 x^{2} - 81 x + 81 = 0

0 = (x - 3) (x - 4) (x - 6)

What are the solutions to the equation 2x^3+7x^2-4x=0 ?
The solutions to the equation 2x^3+7x^2-4x=0 are x=0,x= 1/2 ,x=-4
Find the zeros of 2x^3+7x^2-4x=0
The zeros of 2x^3+7x^2-4x=0 are x=0,x= 1/2 ,x=-4