What is factor x^4+x^3-6x^2-4x+8 ?

The solution to factor x^4+x^3-6x^2-4x+8 is (x-1)(x+2)^2(x-2)

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factor x^4+x^3-6x^2-4x+8

factor

x^{4} + x^{3} - 6 x^{2} - 4 x + 8

(x - 1) (x + 2)^{2} (x - 2)

Solution steps

x^{4} + x^{3} - 6 x^{2} - 4 x + 8

Use the rational root theorem

= (x - 1) \frac{x ^{4} + x ^{3} - 6 x ^{2} - 4 x + 8}{x - 1}

\frac{x ^{4} + x ^{3} - 6 x ^{2} - 4 x + 8}{x - 1} = x^{3} + 2 x^{2} - 4 x - 8

= (x - 1) (x^{3} + 2 x^{2} - 4 x - 8)

Factor

x^{3} + 2 x^{2} - 4 x - 8 : (x + 2) (x + 2) (x - 2)

= (x - 1) (x + 2) (x + 2) (x - 2)

Apply exponent rule:

aa = a^{2}

(x + 2) (x + 2) = (x + 2)^{2}

= (x - 1) (x + 2)^{2} (x - 2)

- \frac{1}{3} x \geq - 9

0. 4^{- 0.15}

\frac{a ^{2} + a - 42}{a ^{2} - a - 30}

(t^{8})^{2}

2 (5 x - 6) = 3 (3 x + 2) + x

What is factor x^4+x^3-6x^2-4x+8 ?
The solution to factor x^4+x^3-6x^2-4x+8 is (x-1)(x+2)^2(x-2)