What are the solutions to the equation 16x^3+16x^2-25x-25=0 ?

The solutions to the equation 16x^3+16x^2-25x-25=0 are x=-1,x=-5/4 ,x= 5/4

Find the zeros of 16x^3+16x^2-25x-25=0

The zeros of 16x^3+16x^2-25x-25=0 are x=-1,x=-5/4 ,x= 5/4

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16 x^{3} + 16 x^{2} - 25 x - 25 = 0

x = - 1, x = - \frac{5}{4}, x = \frac{5}{4}

Decimal Notation

x = - 1, x = - 1.25, x = 1.25

Solution steps

16 x^{3} + 16 x^{2} - 25 x - 25 = 0

Factor

16 x^{3} + 16 x^{2} - 25 x - 25 : (x + 1) (4 x + 5) (4 x - 5)

(x + 1) (4 x + 5) (4 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or 4 x + 5 = 0 or 4 x - 5 = 0

Solve

x + 1 = 0 : x = - 1

Solve

4 x + 5 = 0 : x = - \frac{5}{4}

Solve

4 x - 5 = 0 : x = \frac{5}{4}

The solutions are

x = - 1, x = - \frac{5}{4}, x = \frac{5}{4}

25 t - t^{3} = 0

x^{8} + x^{5} + 1 = 0

x^{5} = 9 x

5 x^{4} = 135 x

6 n^{4} + 9 n^{3} + 3 n^{2} = 0

What are the solutions to the equation 16x^3+16x^2-25x-25=0 ?
The solutions to the equation 16x^3+16x^2-25x-25=0 are x=-1,x=-5/4 ,x= 5/4
Find the zeros of 16x^3+16x^2-25x-25=0
The zeros of 16x^3+16x^2-25x-25=0 are x=-1,x=-5/4 ,x= 5/4