What are the solutions to the equation -x(x-9)(4x+9)=0 ?

The solutions to the equation -x(x-9)(4x+9)=0 are x=0,x=9,x=-9/4

Find the zeros of -x(x-9)(4x+9)=0

The zeros of -x(x-9)(4x+9)=0 are x=0,x=9,x=-9/4

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- x (x - 9) (4 x + 9) = 0

x = 0, x = 9, x = - \frac{9}{4}

Decimal Notation

x = 0, x = 9, x = - 2.25

Solution steps

- x (x - 9) (4 x + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 9 = 0 or 4 x + 9 = 0

Solve

x - 9 = 0 : x = 9

Solve

4 x + 9 = 0 : x = - \frac{9}{4}

The solutions are

x = 0, x = 9, x = - \frac{9}{4}

a^{4} - 2 a^{2} + 1 = 0

a \cdot a^{5} = a

r^{3} = \frac{3}{9}

3^{4} - x^{4} = 0

3 x^{4} + 8 x^{3} + 6 x^{2} + 3 x - 2 = 0

What are the solutions to the equation -x(x-9)(4x+9)=0 ?
The solutions to the equation -x(x-9)(4x+9)=0 are x=0,x=9,x=-9/4
Find the zeros of -x(x-9)(4x+9)=0
The zeros of -x(x-9)(4x+9)=0 are x=0,x=9,x=-9/4