What are the solutions to the equation 16x^3-x=0 ?

The solutions to the equation 16x^3-x=0 are x=0,x=-1/4 ,x= 1/4

Find the zeros of 16x^3-x=0

The zeros of 16x^3-x=0 are x=0,x=-1/4 ,x= 1/4

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16 x^{3} - x = 0

x = 0, x = - \frac{1}{4}, x = \frac{1}{4}

Decimal Notation

x = 0, x = - 0.25, x = 0.25

Solution steps

16 x^{3} - x = 0

Factor

16 x^{3} - x : x (4 x + 1) (4 x - 1)

x (4 x + 1) (4 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 4 x + 1 = 0 or 4 x - 1 = 0

Solve

4 x + 1 = 0 : x = - \frac{1}{4}

Solve

4 x - 1 = 0 : x = \frac{1}{4}

The solutions are

x = 0, x = - \frac{1}{4}, x = \frac{1}{4}

8 k - 48 - 8 k^{8} = k + 15 k

(x (x + 1) (x - 1)) 1 = 2 x - 2

2 x^{3} - 6 x^{2} - 8 x = 0

2 x^{3} - 3 x^{2} - 50 x - 24 = 0

x^{3} - 110 x^{2} - 6996 x + 381196 = 0

What are the solutions to the equation 16x^3-x=0 ?
The solutions to the equation 16x^3-x=0 are x=0,x=-1/4 ,x= 1/4
Find the zeros of 16x^3-x=0
The zeros of 16x^3-x=0 are x=0,x=-1/4 ,x= 1/4