What are the solutions to the equation -2(x+1)^3=16 ?

The solutions to the equation -2(x+1)^3=16 are x=-3,x=sqrt(3)i,x=-sqrt(3)i

Find the zeros of -2(x+1)^3=16

The zeros of -2(x+1)^3=16 are x=-3,x=sqrt(3)i,x=-sqrt(3)i

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- 2 (x + 1)^{3} = 16

x = - 3, x = 3 i, x = - 3 i

Solution steps

- 2 (x + 1)^{3} = 16

Expand

- 2 (x + 1)^{3} : - 2 x^{3} - 6 x^{2} - 6 x - 2

- 2 x^{3} - 6 x^{2} - 6 x - 2 = 16

Move

16

to the left side

- 2 x^{3} - 6 x^{2} - 6 x - 18 = 0

Factor

- 2 x^{3} - 6 x^{2} - 6 x - 18 : - 2 (x + 3) (x^{2} + 3)

- 2 (x + 3) (x^{2} + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x^{2} + 3 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x^{2} + 3 = 0 : x = 3 i, x = - 3 i

The solutions are

x = - 3, x = 3 i, x = - 3 i

t^{3} - 6 t^{2} - 15 t + 40 = 0

x^{4} = 2^{0.5}

2151296 = 400000 (1 + x)^{5}

2 x^{3} - 3 x^{2} + 2 x = - 4 x^{3} + 10 x - 4

x^{4} - 6 x^{2} - 1 = 0

What are the solutions to the equation -2(x+1)^3=16 ?
The solutions to the equation -2(x+1)^3=16 are x=-3,x=sqrt(3)i,x=-sqrt(3)i
Find the zeros of -2(x+1)^3=16
The zeros of -2(x+1)^3=16 are x=-3,x=sqrt(3)i,x=-sqrt(3)i