What are the solutions to the equation 5x^3+4x^2-x=0 ?

The solutions to the equation 5x^3+4x^2-x=0 are x=0,x= 1/5 ,x=-1

Find the zeros of 5x^3+4x^2-x=0

The zeros of 5x^3+4x^2-x=0 are x=0,x= 1/5 ,x=-1

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5 x^{3} + 4 x^{2} - x = 0

x = 0, x = \frac{1}{5}, x = - 1

Decimal Notation

x = 0, x = 0.2, x = - 1

Solution steps

5 x^{3} + 4 x^{2} - x = 0

Factor

5 x^{3} + 4 x^{2} - x : x (5 x - 1) (x + 1)

x (5 x - 1) (x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 5 x - 1 = 0 or x + 1 = 0

Solve

5 x - 1 = 0 : x = \frac{1}{5}

Solve

x + 1 = 0 : x = - 1

The solutions are

x = 0, x = \frac{1}{5}, x = - 1

5 x^{3} + 25 x^{2} + 62 x - 6 = 0

10 = 3 x^{3} - 2

a = (x + 1) (x - 1) (x^{2} + 1) + 1

(12 x^{5} - 12 x^{2})^{3} = 0

x^{6} - 9 x^{3} + 14 = 0

What are the solutions to the equation 5x^3+4x^2-x=0 ?
The solutions to the equation 5x^3+4x^2-x=0 are x=0,x= 1/5 ,x=-1
Find the zeros of 5x^3+4x^2-x=0
The zeros of 5x^3+4x^2-x=0 are x=0,x= 1/5 ,x=-1