What are the solutions to the equation 12y^3-28y^2-9y+10=0 ?

The solutions to the equation 12y^3-28y^2-9y+10=0 are y= 1/2 ,y=-2/3 ,y= 5/2

Find the zeros of 12y^3-28y^2-9y+10=0

The zeros of 12y^3-28y^2-9y+10=0 are y= 1/2 ,y=-2/3 ,y= 5/2

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12 y^{3} - 28 y^{2} - 9 y + 10 = 0

y = \frac{1}{2}, y = - \frac{2}{3}, y = \frac{5}{2}

Decimal Notation

y = 0.5, y = - 0.66666 \dots, y = 2.5

Solution steps

12 y^{3} - 28 y^{2} - 9 y + 10 = 0

Factor

12 y^{3} - 28 y^{2} - 9 y + 10 : (2 y - 1) (3 y + 2) (2 y - 5)

(2 y - 1) (3 y + 2) (2 y - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 y - 1 = 0 or 3 y + 2 = 0 or 2 y - 5 = 0

Solve

2 y - 1 = 0 : y = \frac{1}{2}

Solve

3 y + 2 = 0 : y = - \frac{2}{3}

Solve

2 y - 5 = 0 : y = \frac{5}{2}

The solutions are

y = \frac{1}{2}, y = - \frac{2}{3}, y = \frac{5}{2}

2 x^{3} - 2 x^{2} + 5 x = 8

x^{3} = 35

\frac{6 x ^{4}}{3} = 32

x^{3} = 63

45 x^{3} - 72 x^{2} + 37 x - 6 = 0

What are the solutions to the equation 12y^3-28y^2-9y+10=0 ?
The solutions to the equation 12y^3-28y^2-9y+10=0 are y= 1/2 ,y=-2/3 ,y= 5/2
Find the zeros of 12y^3-28y^2-9y+10=0
The zeros of 12y^3-28y^2-9y+10=0 are y= 1/2 ,y=-2/3 ,y= 5/2