What are the solutions to the equation r^3+1=0 ?

The solutions to the equation r^3+1=0 are r=-1,r= 1/2-(sqrt(3))/2 i,r= 1/2+(sqrt(3))/2 i

Find the zeros of r^3+1=0

The zeros of r^3+1=0 are r=-1,r= 1/2-(sqrt(3))/2 i,r= 1/2+(sqrt(3))/2 i

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r^{3} + 1 = 0

r = - 1, r = \frac{1}{2} - \frac{3}{2} i, r = \frac{1}{2} + \frac{3}{2} i

Solution steps

r^{3} + 1 = 0

Move

1

to the right side

r^{3} = - 1

For

x^{3} = f (a)

the solutions are

Simplify

r = - 1, r = \frac{1}{2} - \frac{3}{2} i, r = \frac{1}{2} + \frac{3}{2} i

x^{5} = 32 i

- 2 x^{3} - 2 x^{2} + 1 = 0

12500 = 10000 (1 + X)^{10}

x^{4} - 1 0^{2} + 16 = 0

(x - 4)^{4} - 80 = 0

What are the solutions to the equation r^3+1=0 ?
The solutions to the equation r^3+1=0 are r=-1,r= 1/2-(sqrt(3))/2 i,r= 1/2+(sqrt(3))/2 i
Find the zeros of r^3+1=0
The zeros of r^3+1=0 are r=-1,r= 1/2-(sqrt(3))/2 i,r= 1/2+(sqrt(3))/2 i