What are the solutions to the equation 6x^3-23x^2+26x-8=0 ?

The solutions to the equation 6x^3-23x^2+26x-8=0 are x=2,x= 1/2 ,x= 4/3

Find the zeros of 6x^3-23x^2+26x-8=0

The zeros of 6x^3-23x^2+26x-8=0 are x=2,x= 1/2 ,x= 4/3

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6 x^{3} - 23 x^{2} + 26 x - 8 = 0

x = 2, x = \frac{1}{2}, x = \frac{4}{3}

Decimal Notation

x = 2, x = 0.5, x = 1.33333 \dots

Solution steps

6 x^{3} - 23 x^{2} + 26 x - 8 = 0

Factor

6 x^{3} - 23 x^{2} + 26 x - 8 : (x - 2) (2 x - 1) (3 x - 4)

(x - 2) (2 x - 1) (3 x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or 2 x - 1 = 0 or 3 x - 4 = 0

Solve

x - 2 = 0 : x = 2

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

3 x - 4 = 0 : x = \frac{4}{3}

The solutions are

x = 2, x = \frac{1}{2}, x = \frac{4}{3}

x^{5} = - 13

x^{3} + 3 = - 5

x^{543} = 7

x, I n (x^{4}) = 0.7

3 x^{3} - 21 x^{2} - 90 x = 0

What are the solutions to the equation 6x^3-23x^2+26x-8=0 ?
The solutions to the equation 6x^3-23x^2+26x-8=0 are x=2,x= 1/2 ,x= 4/3
Find the zeros of 6x^3-23x^2+26x-8=0
The zeros of 6x^3-23x^2+26x-8=0 are x=2,x= 1/2 ,x= 4/3