What are the solutions to the equation y^3=-3y^4 ?

The solutions to the equation y^3=-3y^4 are y=0,y=-1/3

Find the zeros of y^3=-3y^4

The zeros of y^3=-3y^4 are y=0,y=-1/3

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y^{3} = - 3 y^{4}

y = 0, y = - \frac{1}{3}

Decimal Notation

y = 0, y = - 0.33333 \dots

Solution steps

y^{3} = - 3 y^{4}

Switch sides

- 3 y^{4} = y^{3}

Move

y^{3}

to the left side

- 3 y^{4} - y^{3} = 0

Factor

- 3 y^{4} - y^{3} : - y^{3} (3 y + 1)

- y^{3} (3 y + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or 3 y + 1 = 0

Solve

3 y + 1 = 0 : y = - \frac{1}{3}

The solutions are

y = 0, y = - \frac{1}{3}

16 x^{4} - 121 x^{2} = 0

- x^{4} + 4 x^{3} - 18 x^{2} + 16 x + 8 = 0

x (x + 1) (x + 2) (x + 3) = 46 1^{2} - 1

3 x^{3} - 2 x^{2} - 21 x + 14 = 0

473 = \frac{7 π x ^{3}}{48}

What are the solutions to the equation y^3=-3y^4 ?
The solutions to the equation y^3=-3y^4 are y=0,y=-1/3
Find the zeros of y^3=-3y^4
The zeros of y^3=-3y^4 are y=0,y=-1/3