What are the solutions to the equation x(x-2)(x+2)=0 ?

The solutions to the equation x(x-2)(x+2)=0 are x=0,x=2,x=-2

Find the zeros of x(x-2)(x+2)=0

The zeros of x(x-2)(x+2)=0 are x=0,x=2,x=-2

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x (x - 2) (x + 2) = 0

x = 0, x = 2, x = - 2

Solution steps

x (x - 2) (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 2 = 0 or x + 2 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 2 = 0 : x = - 2

The solutions are

x = 0, x = 2, x = - 2

13 e^{9} e + 4 = - 5 e + 14 + 13 e^{9}

x^{4} - 3 x^{3} + 4 x^{2} - 3 x + 1 = 0

4 x^{3} - 3 x^{2} = 0

9 y^{4} + 65 y^{2} - 144 = 0

x^{3} - 4 x^{2} - x - 1 = 0

What are the solutions to the equation x(x-2)(x+2)=0 ?
The solutions to the equation x(x-2)(x+2)=0 are x=0,x=2,x=-2
Find the zeros of x(x-2)(x+2)=0
The zeros of x(x-2)(x+2)=0 are x=0,x=2,x=-2