What are the solutions to the equation v^2+5v+4=0 ?

The solutions to the equation v^2+5v+4=0 are v=-1,v=-4

Find the zeros of v^2+5v+4=0

The zeros of v^2+5v+4=0 are v=-1,v=-4

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v^{2} + 5 v + 4 = 0

v = - 1, v = - 4

Solution steps

v^{2} + 5 v + 4 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 4 = 3

v_{1, 2} = \frac{- 5 \pm 3}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 5 + 3}{2 \cdot 1}, v_{2} = \frac{- 5 - 3}{2 \cdot 1}

v = \frac{- 5 + 3}{2 \cdot 1} : - 1

v = \frac{- 5 - 3}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

v = - 1, v = - 4

x^{3} + 7 x^{2} + 16 x + 112

\frac{( 3 + 8 i ) ^{4}}{( 1 + i ) ^{10}}

s^{2} + 5 s + 100 = 0

∣ 2 - 3 x ∣ > 1

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What are the solutions to the equation v^2+5v+4=0 ?
The solutions to the equation v^2+5v+4=0 are v=-1,v=-4
Find the zeros of v^2+5v+4=0
The zeros of v^2+5v+4=0 are v=-1,v=-4