What are the solutions to the equation (r-1)^4(r+1)=0 ?

The solutions to the equation (r-1)^4(r+1)=0 are r=1,r=-1

Find the zeros of (r-1)^4(r+1)=0

The zeros of (r-1)^4(r+1)=0 are r=1,r=-1

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(r - 1)^{4} (r + 1) = 0

r = 1, r = - 1

Solution steps

(r - 1)^{4} (r + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

r - 1 = 0 or r + 1 = 0

Solve

r - 1 = 0 : r = 1

Solve

r + 1 = 0 : r = - 1

The solutions are

r = 1, r = - 1

x^{4} + x^{3} = 3 - 4 x

2 x^{3} - 3 x + 6 = 0

2 x^{3} + 6 x^{2} + 6 x = 0

x, u = x^{3} + y^{3}

y, 9 + y^{3} = - x

What are the solutions to the equation (r-1)^4(r+1)=0 ?
The solutions to the equation (r-1)^4(r+1)=0 are r=1,r=-1
Find the zeros of (r-1)^4(r+1)=0
The zeros of (r-1)^4(r+1)=0 are r=1,r=-1