What are the solutions to the equation 39=x^5+x+5 ?

The solutions to the equation 39=x^5+x+5 are x=2

Find the zeros of 39=x^5+x+5

The zeros of 39=x^5+x+5 are x=2

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39 = x^{5} + x + 5

x = 2

Solution steps

39 = x^{5} + x + 5

Switch sides

x^{5} + x + 5 = 39

Move

39

to the left side

x^{5} + x - 34 = 0

Factor

x^{5} + x - 34 : (x - 2) (x^{4} + 2 x^{3} + 4 x^{2} + 8 x + 17)

(x - 2) (x^{4} + 2 x^{3} + 4 x^{2} + 8 x + 17) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x^{4} + 2 x^{3} + 4 x^{2} + 8 x + 17 = 0

Solve

x - 2 = 0 : x = 2

Solve

x^{4} + 2 x^{3} + 4 x^{2} + 8 x + 17 = 0 :

No Solution for

x \in R

The solution is

x = 2

z^{3} = \frac{1}{8} i

49 x^{4} - 25 x^{2} = 0

x^{(4)} - 4 x^{(2)} + 3 = 0

r^{4} + 9 r^{2} = 0

x (x - 2)^{2} - 3 = 7

What are the solutions to the equation 39=x^5+x+5 ?
The solutions to the equation 39=x^5+x+5 are x=2
Find the zeros of 39=x^5+x+5
The zeros of 39=x^5+x+5 are x=2