What are the solutions to the equation 6x^2-3=7x ?

The solutions to the equation 6x^2-3=7x are x= 3/2 ,x=-1/3

Find the zeros of 6x^2-3=7x

The zeros of 6x^2-3=7x are x= 3/2 ,x=-1/3

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6 x^{2} - 3 = 7 x

x = \frac{3}{2}, x = - \frac{1}{3}

Decimal Notation

x = 1.5, x = - 0.33333 \dots

Solution steps

6 x^{2} - 3 = 7 x

Move

7 x

to the left side

6 x^{2} - 3 - 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

6 x^{2} - 7 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 6 ( - 3 )}{2 \cdot 6}

(- 7)^{2} - 4 \cdot 6 (- 3) = 11

x_{1, 2} = \frac{- ( - 7 ) \pm 11}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 11}{2 \cdot 6}, x_{2} = \frac{- ( - 7 ) - 11}{2 \cdot 6}

x = \frac{- ( - 7 ) + 11}{2 \cdot 6} : \frac{3}{2}

x = \frac{- ( - 7 ) - 11}{2 \cdot 6} : - \frac{1}{3}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - \frac{1}{3}

∣ x - 3 ∣ - 4 = 5

4 w^{2} - 25

\frac{x - 4}{2 x + 4} \geq 1

6 x^{2} = - 3

(6 4^{3}) \frac{1}{3}

What are the solutions to the equation 6x^2-3=7x ?
The solutions to the equation 6x^2-3=7x are x= 3/2 ,x=-1/3
Find the zeros of 6x^2-3=7x
The zeros of 6x^2-3=7x are x= 3/2 ,x=-1/3