What are the solutions to the equation 6b^3-7b^2+2b=0 ?

The solutions to the equation 6b^3-7b^2+2b=0 are b=0,b= 1/2 ,b= 2/3

Find the zeros of 6b^3-7b^2+2b=0

The zeros of 6b^3-7b^2+2b=0 are b=0,b= 1/2 ,b= 2/3

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6 b^{3} - 7 b^{2} + 2 b = 0

b = 0, b = \frac{1}{2}, b = \frac{2}{3}

Decimal Notation

b = 0, b = 0.5, b = 0.66666 \dots

Solution steps

6 b^{3} - 7 b^{2} + 2 b = 0

Factor

6 b^{3} - 7 b^{2} + 2 b : b (2 b - 1) (3 b - 2)

b (2 b - 1) (3 b - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

b = 0 or 2 b - 1 = 0 or 3 b - 2 = 0

Solve

2 b - 1 = 0 : b = \frac{1}{2}

Solve

3 b - 2 = 0 : b = \frac{2}{3}

The solutions are

b = 0, b = \frac{1}{2}, b = \frac{2}{3}

1 - x^{2} = x^{4} - 2 x^{2} + 1

4 x^{2} (4 x^{2} - 10) = - 9

- x^{3} - 3 x + 1 = 0

16 y^{4} - 8 y^{2} + 1 = 0

3 d^{8} - d^{7} = 0

What are the solutions to the equation 6b^3-7b^2+2b=0 ?
The solutions to the equation 6b^3-7b^2+2b=0 are b=0,b= 1/2 ,b= 2/3
Find the zeros of 6b^3-7b^2+2b=0
The zeros of 6b^3-7b^2+2b=0 are b=0,b= 1/2 ,b= 2/3