What are the solutions to the equation 2x^3+11x^2+13x+4=0 ?

The solutions to the equation 2x^3+11x^2+13x+4=0 are x=-1,x=-1/2 ,x=-4

Find the zeros of 2x^3+11x^2+13x+4=0

The zeros of 2x^3+11x^2+13x+4=0 are x=-1,x=-1/2 ,x=-4

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2 x^{3} + 11 x^{2} + 13 x + 4 = 0

x = - 1, x = - \frac{1}{2}, x = - 4

Decimal Notation

x = - 1, x = - 0.5, x = - 4

Solution steps

2 x^{3} + 11 x^{2} + 13 x + 4 = 0

Factor

2 x^{3} + 11 x^{2} + 13 x + 4 : (x + 1) (2 x + 1) (x + 4)

(x + 1) (2 x + 1) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or 2 x + 1 = 0 or x + 4 = 0

Solve

x + 1 = 0 : x = - 1

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

x + 4 = 0 : x = - 4

The solutions are

x = - 1, x = - \frac{1}{2}, x = - 4

z^{6} - 7 z^{3} - 8 = 0

2 y = y^{3} - y

371 = \frac{4}{3} π r^{3}

x^{3} - x^{2} + x = 6

\frac{4}{3} π r^{3} = 4 π r^{2}

What are the solutions to the equation 2x^3+11x^2+13x+4=0 ?
The solutions to the equation 2x^3+11x^2+13x+4=0 are x=-1,x=-1/2 ,x=-4
Find the zeros of 2x^3+11x^2+13x+4=0
The zeros of 2x^3+11x^2+13x+4=0 are x=-1,x=-1/2 ,x=-4