What are the solutions to the equation (x-1)(x+1)(x+2)=-2 ?

The solutions to the equation (x-1)(x+1)(x+2)=-2 are x=0,x=-1+sqrt(2),x=-1-sqrt(2)

Find the zeros of (x-1)(x+1)(x+2)=-2

The zeros of (x-1)(x+1)(x+2)=-2 are x=0,x=-1+sqrt(2),x=-1-sqrt(2)

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(x - 1) (x + 1) (x + 2) = - 2

x = 0, x = - 1 + 2, x = - 1 - 2

Decimal Notation

x = 0, x = 0.41421 \dots, x = - 2.41421 \dots

Solution steps

(x - 1) (x + 1) (x + 2) = - 2

Expand

(x - 1) (x + 1) (x + 2) : x^{3} + 2 x^{2} - x - 2

x^{3} + 2 x^{2} - x - 2 = - 2

Move

2

to the left side

x^{3} + 2 x^{2} - x = 0

Factor

x^{3} + 2 x^{2} - x : x (x^{2} + 2 x - 1)

x (x^{2} + 2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} + 2 x - 1 = 0

Solve

x^{2} + 2 x - 1 = 0 : x = - 1 + 2, x = - 1 - 2

The solutions are

x = 0, x = - 1 + 2, x = - 1 - 2

x^{2} (x - 2)^{2} (x - 1)^{2} = 0

x^{3} = 9000

2 = y^{3}

y^{4} + 27 y^{2} - 324 = 0

2 x^{5} - 6 x^{4} - 80 x^{3} = 0

What are the solutions to the equation (x-1)(x+1)(x+2)=-2 ?
The solutions to the equation (x-1)(x+1)(x+2)=-2 are x=0,x=-1+sqrt(2),x=-1-sqrt(2)
Find the zeros of (x-1)(x+1)(x+2)=-2
The zeros of (x-1)(x+1)(x+2)=-2 are x=0,x=-1+sqrt(2),x=-1-sqrt(2)