What are the solutions to the equation d^2(d^2+1)=0 ?

The solutions to the equation d^2(d^2+1)=0 are d=0,d=i,d=-i

Find the zeros of d^2(d^2+1)=0

The zeros of d^2(d^2+1)=0 are d=0,d=i,d=-i

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d^{2} (d^{2} + 1) = 0

d = 0, d = i, d = - i

Solution steps

d^{2} (d^{2} + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

d = 0 or d^{2} + 1 = 0

Solve

d^{2} + 1 = 0 : d = i, d = - i

The solutions are

d = 0, d = i, d = - i

d^{2} (d^{2} + 1) = 1

y^{3} = - 125

x^{3} + 3 x^{2} - 25 x + 21 = 0

(x^{2} + 2 x)^{2} = 2 x^{2} + 4 x + 3

p^{3} - 144 p = 0

What are the solutions to the equation d^2(d^2+1)=0 ?
The solutions to the equation d^2(d^2+1)=0 are d=0,d=i,d=-i
Find the zeros of d^2(d^2+1)=0
The zeros of d^2(d^2+1)=0 are d=0,d=i,d=-i