What are the solutions to the equation x^{(4)}-29x^{(2)}+100=0 ?

The solutions to the equation x^{(4)}-29x^{(2)}+100=0 are x=5,x=-5,x=2,x=-2

Find the zeros of x^{(4)}-29x^{(2)}+100=0

The zeros of x^{(4)}-29x^{(2)}+100=0 are x=5,x=-5,x=2,x=-2

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x^{(4)} - 29 x^{(2)} + 100 = 0

x = 5, x = - 5, x = 2, x = - 2

Solution steps

x^{(4)} - 29 x^{(2)} + 100 = 0

Refine

x^{4} - 29 x^{2} + 100 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

u^{2} - 29 u + 100 = 0

Solve

u^{2} - 29 u + 100 = 0 : u = 25, u = 4

u = 25, u = 4

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 25 : x = 5, x = - 5

Solve

x^{2} = 4 : x = 2, x = - 2

The solutions are

x = 5, x = - 5, x = 2, x = - 2

- 2 x^{3} - 4 x^{2} + 10 x + 12 = 0

x, x^{4} - 11 x^{2} + 10 = 0

y^{3} + y^{2} = 25 y + 25

x^{4} + 24 x^{2} + 9 = 0

F, d - F^{3} = 4 a

What are the solutions to the equation x^{(4)}-29x^{(2)}+100=0 ?
The solutions to the equation x^{(4)}-29x^{(2)}+100=0 are x=5,x=-5,x=2,x=-2
Find the zeros of x^{(4)}-29x^{(2)}+100=0
The zeros of x^{(4)}-29x^{(2)}+100=0 are x=5,x=-5,x=2,x=-2