What are the solutions to the equation (3x+5)^4-(3x+5)^3=0 ?

The solutions to the equation (3x+5)^4-(3x+5)^3=0 are x=-5/3 ,x=-4/3

Find the zeros of (3x+5)^4-(3x+5)^3=0

The zeros of (3x+5)^4-(3x+5)^3=0 are x=-5/3 ,x=-4/3

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(3 x + 5)^{4} - (3 x + 5)^{3} = 0

x = - \frac{5}{3}, x = - \frac{4}{3}

Decimal Notation

x = - 1.66666 \dots, x = - 1.33333 \dots

Solution steps

(3 x + 5)^{4} - (3 x + 5)^{3} = 0

Factor

(3 x + 5)^{4} - (3 x + 5)^{3} : (3 x + 5)^{3} (3 x + 4)

(3 x + 5)^{3} (3 x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 5 = 0 or 3 x + 4 = 0

Solve

3 x + 5 = 0 : x = - \frac{5}{3}

Solve

3 x + 4 = 0 : x = - \frac{4}{3}

The solutions are

x = - \frac{5}{3}, x = - \frac{4}{3}

268 = r^{4}

4 x^{3} - 3 x^{2} + 1 = 0

9 x^{3} + 45 x^{2} + 66 x + 36 = 0

9 x^{6} - 36 x^{3} + 36 = 0

x^{3} + 3 x + 7 = 0

What are the solutions to the equation (3x+5)^4-(3x+5)^3=0 ?
The solutions to the equation (3x+5)^4-(3x+5)^3=0 are x=-5/3 ,x=-4/3
Find the zeros of (3x+5)^4-(3x+5)^3=0
The zeros of (3x+5)^4-(3x+5)^3=0 are x=-5/3 ,x=-4/3