What are the solutions to the equation (x)=5x^5-3x^3+4x+5 ?

The solutions to the equation (x)=5x^5-3x^3+4x+5 are x=-1

Find the zeros of (x)=5x^5-3x^3+4x+5

The zeros of (x)=5x^5-3x^3+4x+5 are x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x) = 5 x^{5} - 3 x^{3} + 4 x + 5

x = - 1

Solution steps

(x) = 5 x^{5} - 3 x^{3} + 4 x + 5

Refine

x = 5 x^{5} - 3 x^{3} + 4 x + 5

Switch sides

5 x^{5} - 3 x^{3} + 4 x + 5 = x

Move

x

to the left side

5 x^{5} - 3 x^{3} + 3 x + 5 = 0

Factor

5 x^{5} - 3 x^{3} + 3 x + 5 : (x + 1) (5 x^{4} - 5 x^{3} + 2 x^{2} - 2 x + 5)

(x + 1) (5 x^{4} - 5 x^{3} + 2 x^{2} - 2 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or 5 x^{4} - 5 x^{3} + 2 x^{2} - 2 x + 5 = 0

Solve

x + 1 = 0 : x = - 1

Solve

5 x^{4} - 5 x^{3} + 2 x^{2} - 2 x + 5 = 0 :

No Solution for

x \in R

The solution is

x = - 1

x, x^{4} - 18 x^{2} + 81 = 0

(4^{2} + x)^{4} = 16

2 x^{3} + 3 x^{2} + 3 + 2 x = 0

x^{9} - 4 x^{7} - x^{6} + 4 x^{4} = 0

w, a = \frac{p w ^{4}}{q}

What are the solutions to the equation (x)=5x^5-3x^3+4x+5 ?
The solutions to the equation (x)=5x^5-3x^3+4x+5 are x=-1
Find the zeros of (x)=5x^5-3x^3+4x+5
The zeros of (x)=5x^5-3x^3+4x+5 are x=-1