What are the solutions to the equation 25b^3-4b=0 ?

The solutions to the equation 25b^3-4b=0 are b=0,b=-2/5 ,b= 2/5

Find the zeros of 25b^3-4b=0

The zeros of 25b^3-4b=0 are b=0,b=-2/5 ,b= 2/5

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25 b^{3} - 4 b = 0

b = 0, b = - \frac{2}{5}, b = \frac{2}{5}

Decimal Notation

b = 0, b = - 0.4, b = 0.4

Solution steps

25 b^{3} - 4 b = 0

Factor

25 b^{3} - 4 b : b (5 b + 2) (5 b - 2)

b (5 b + 2) (5 b - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

b = 0 or 5 b + 2 = 0 or 5 b - 2 = 0

Solve

5 b + 2 = 0 : b = - \frac{2}{5}

Solve

5 b - 2 = 0 : b = \frac{2}{5}

The solutions are

b = 0, b = - \frac{2}{5}, b = \frac{2}{5}

x^{3} - 3333 = 4443 + 5553

u^{3} + 1 = 0

2 x^{3} - 9 x^{2} + 30 x - 13 = 0

x^{6} - 5 \cdot 3 + 6 = 0

3 y^{3} - 3 y^{2} + 1 = 0

What are the solutions to the equation 25b^3-4b=0 ?
The solutions to the equation 25b^3-4b=0 are b=0,b=-2/5 ,b= 2/5
Find the zeros of 25b^3-4b=0
The zeros of 25b^3-4b=0 are b=0,b=-2/5 ,b= 2/5