What are the solutions to the equation s^2+4s+20=0 ?

The solutions to the equation s^2+4s+20=0 are s=-2+4i,s=-2-4i

Find the zeros of s^2+4s+20=0

The zeros of s^2+4s+20=0 are s=-2+4i,s=-2-4i

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s^{2} + 4 s + 20 = 0

s = - 2 + 4 i, s = - 2 - 4 i

Solution steps

s^{2} + 4 s + 20 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 20 : 8 i

s_{1, 2} = \frac{- 4 \pm 8 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 4 + 8 i}{2 \cdot 1}, s_{2} = \frac{- 4 - 8 i}{2 \cdot 1}

s = \frac{- 4 + 8 i}{2 \cdot 1} : - 2 + 4 i

s = \frac{- 4 - 8 i}{2 \cdot 1} : - 2 - 4 i

The solutions to the quadratic equation are:

s = - 2 + 4 i, s = - 2 - 4 i

11 - 3 r^{2} = - 49

7 - (4 x - 3) = 9 (- 6 + 3 x)

\frac{2 x - 3}{6} = \frac{2 x}{3} + \frac{1}{2}

2 ln (4) - ln (2)

2 (2 x + 3) = x + 9

What are the solutions to the equation s^2+4s+20=0 ?
The solutions to the equation s^2+4s+20=0 are s=-2+4i,s=-2-4i
Find the zeros of s^2+4s+20=0
The zeros of s^2+4s+20=0 are s=-2+4i,s=-2-4i