What are the solutions to the equation (x^3+4x^2)=(9x+36) ?

The solutions to the equation (x^3+4x^2)=(9x+36) are x=-4,x=-3,x=3

Find the zeros of (x^3+4x^2)=(9x+36)

The zeros of (x^3+4x^2)=(9x+36) are x=-4,x=-3,x=3

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(x^{3} + 4 x^{2}) = (9 x + 36)

x = - 4, x = - 3, x = 3

Solution steps

(x^{3} + 4 x^{2}) = (9 x + 36)

Refine

x^{3} + 4 x^{2} = 9 x + 36

Move

36

to the left side

x^{3} + 4 x^{2} - 36 = 9 x

Move

9 x

to the left side

x^{3} + 4 x^{2} - 36 - 9 x = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

x^{3} + 4 x^{2} - 9 x - 36 = 0

Factor

x^{3} + 4 x^{2} - 9 x - 36 : (x + 4) (x + 3) (x - 3)

(x + 4) (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0 or x + 3 = 0 or x - 3 = 0

Solve

x + 4 = 0 : x = - 4

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = - 4, x = - 3, x = 3

10 = (1 + n)^{8}

z^{3} + 5 z^{2} + 4 z = 100

a^{28} = 1^{0} + (28 - 1) (1)

x (x + 3)^{3} - 28 (x + 3)^{2} = 0

y^{3} = 16

What are the solutions to the equation (x^3+4x^2)=(9x+36) ?
The solutions to the equation (x^3+4x^2)=(9x+36) are x=-4,x=-3,x=3
Find the zeros of (x^3+4x^2)=(9x+36)
The zeros of (x^3+4x^2)=(9x+36) are x=-4,x=-3,x=3