What are the solutions to the equation q^3-10q^2-5808=0 ?

The solutions to the equation q^3-10q^2-5808=0 are q=22,q=-6+2sqrt(57)i,q=-6-2sqrt(57)i

Find the zeros of q^3-10q^2-5808=0

The zeros of q^3-10q^2-5808=0 are q=22,q=-6+2sqrt(57)i,q=-6-2sqrt(57)i

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q^{3} - 10 q^{2} - 5808 = 0

q = 22, q = - 6 + 257 i, q = - 6 - 257 i

Solution steps

q^{3} - 10 q^{2} - 5808 = 0

Factor

q^{3} - 10 q^{2} - 5808 : (q - 22) (q^{2} + 12 q + 264)

(q - 22) (q^{2} + 12 q + 264) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

q - 22 = 0 or q^{2} + 12 q + 264 = 0

Solve

q - 22 = 0 : q = 22

Solve

q^{2} + 12 q + 264 = 0 : q = - 6 + 257 i, q = - 6 - 257 i

The solutions are

q = 22, q = - 6 + 257 i, q = - 6 - 257 i

1.05 = (1 + \frac{x}{12})^{12}

3 s^{4} - 14 s^{3} + 20 s^{2} + 10 s + 4 = 0

5 x^{3} - 2 (x^{3} + x) = - x

2 x^{4} - 16 x^{3} + 32 x^{2} + 5 = 0

5 x^{16} = 10 x + 15

What are the solutions to the equation q^3-10q^2-5808=0 ?
The solutions to the equation q^3-10q^2-5808=0 are q=22,q=-6+2sqrt(57)i,q=-6-2sqrt(57)i
Find the zeros of q^3-10q^2-5808=0
The zeros of q^3-10q^2-5808=0 are q=22,q=-6+2sqrt(57)i,q=-6-2sqrt(57)i