What are the solutions to the equation 28x^3+16x^2-80x=0 ?

The solutions to the equation 28x^3+16x^2-80x=0 are x=0,x= 10/7 ,x=-2

Find the zeros of 28x^3+16x^2-80x=0

The zeros of 28x^3+16x^2-80x=0 are x=0,x= 10/7 ,x=-2

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28 x^{3} + 16 x^{2} - 80 x = 0

x = 0, x = \frac{10}{7}, x = - 2

Decimal Notation

x = 0, x = 1.42857 \dots, x = - 2

Solution steps

28 x^{3} + 16 x^{2} - 80 x = 0

Factor

28 x^{3} + 16 x^{2} - 80 x : 4 x (7 x - 10) (x + 2)

4 x (7 x - 10) (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 7 x - 10 = 0 or x + 2 = 0

Solve

7 x - 10 = 0 : x = \frac{10}{7}

Solve

x + 2 = 0 : x = - 2

The solutions are

x = 0, x = \frac{10}{7}, x = - 2

7.8 x^{2} + x^{3} - 0.0317 = 0

x^{5} - 2 x^{4} + x^{3} = 0

(- x)^{8} = - (x)^{8}

735 = 8 (1 + x)^{29}

3 x^{2} 5 x = 2

What are the solutions to the equation 28x^3+16x^2-80x=0 ?
The solutions to the equation 28x^3+16x^2-80x=0 are x=0,x= 10/7 ,x=-2
Find the zeros of 28x^3+16x^2-80x=0
The zeros of 28x^3+16x^2-80x=0 are x=0,x= 10/7 ,x=-2