What are the solutions to the equation -2x(x^2-5)(x^2+1)=0 ?

The solutions to the equation -2x(x^2-5)(x^2+1)=0 are x=0,x=i,x=-i,x=-sqrt(5),x=sqrt(5)

Find the zeros of -2x(x^2-5)(x^2+1)=0

The zeros of -2x(x^2-5)(x^2+1)=0 are x=0,x=i,x=-i,x=-sqrt(5),x=sqrt(5)

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- 2 x (x^{2} - 5) (x^{2} + 1) = 0

x = 0, x = i, x = - i, x = - 5, x = 5

Solution steps

- 2 x (x^{2} - 5) (x^{2} + 1) = 0

Factor

- 2 x (x^{2} - 5) (x^{2} + 1) : - 2 x (x^{2} + 1) (x + 5) (x - 5)

- 2 x (x^{2} + 1) (x + 5) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} + 1 = 0 or x + 5 = 0 or x - 5 = 0

Solve

x^{2} + 1 = 0 : x = i, x = - i

Solve

x + 5 = 0 : x = - 5

Solve

x - 5 = 0 : x = 5

The solutions are

x = 0, x = i, x = - i, x = - 5, x = 5

x (x^{2} - 3)^{3} - 2 = 1785

\frac{3}{16} = 3 r^{4}

x^{4} - 7 x^{2} - 5 = 0

2 x^{3} + 5 x + 7 = 0

x x^{2} + 5 x + 2 = - 4

What are the solutions to the equation -2x(x^2-5)(x^2+1)=0 ?
The solutions to the equation -2x(x^2-5)(x^2+1)=0 are x=0,x=i,x=-i,x=-sqrt(5),x=sqrt(5)
Find the zeros of -2x(x^2-5)(x^2+1)=0
The zeros of -2x(x^2-5)(x^2+1)=0 are x=0,x=i,x=-i,x=-sqrt(5),x=sqrt(5)