What is -x^2-12x-32>0 ?

The solution to -x^2-12x-32>0 is -8<x<-4

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-x^2-12x-32>0

- x^{2} - 12 x - 32 > 0

- 8 < x < - 4

Interval Notation

(- 8, - 4)

Solution steps

- x^{2} - 12 x - 32 > 0

Factor

- x^{2} - 12 x - 32 : - (x + 4) (x + 8)

- (x + 4) (x + 8) > 0

Multiply both sides by

- 1

(reverse the inequality)

(- (x + 4) (x + 8)) (- 1) < 0 \cdot (- 1)

Simplify

(x + 4) (x + 8) < 0

Identify the intervals

- 8 < x < - 4

2 p + 8 = 20 - p

64 x^{9} + 72 x^{6} + 432 x^{3} + 216

\frac{2 - 3 i}{1 - 2 i} + \frac{i}{4 + 3 i}

- 5 < x

7 x^{2} - x - 6 = 0