What are the solutions to the equation (1+x)^{12}=10968 ?

The solutions to the equation (1+x)^{12}=10968 are x=\sqrt[12]{10968}-1,x=-\sqrt[12]{10968}-1

Find the zeros of (1+x)^{12}=10968

The zeros of (1+x)^{12}=10968 are x=\sqrt[12]{10968}-1,x=-\sqrt[12]{10968}-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(1 + x)^{12} = 10968

Decimal Notation

x = 1.17108 \dots, x = - 3.17108 \dots

Solution steps

(1 + x)^{12} = 10968

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

- 2 x^{2} + x^{3} + 1 = 0

19.6 y^{3} - 40.57 y^{2} + 25 = 0

(8 x^{7}) + (8 x^{4}) = 8 x (x)

x^{4} + i x = i x - i + 3

x^{4} + 6 \cdot x^{2} - 60 x + 36 = 0

What are the solutions to the equation (1+x)^{12}=10968 ?
The solutions to the equation (1+x)^{12}=10968 are x=\sqrt[12]{10968}-1,x=-\sqrt[12]{10968}-1
Find the zeros of (1+x)^{12}=10968
The zeros of (1+x)^{12}=10968 are x=\sqrt[12]{10968}-1,x=-\sqrt[12]{10968}-1