What are the solutions to the equation (r^2+1)^4=0 ?

The solutions to the equation (r^2+1)^4=0 are r=i,r=-i

Find the zeros of (r^2+1)^4=0

The zeros of (r^2+1)^4=0 are r=i,r=-i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(r^{2} + 1)^{4} = 0

r = i, r = - i

Solution steps

(r^{2} + 1)^{4} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

r^{2} + 1 = 0

Solve

r^{2} + 1 = 0 : r = i, r = - i

The solutions are

r = i, r = - i

- 5 x^{1} + 8 x^{2} + 10 x^{3} = - 8

3 x^{3} - 2 = 0

x^{4} - 6 x^{2} + 8 x - 1 = 0

a, (a - b)^{3} = 0

x^{3} - 30 x^{2} + 1 5^{3} = 0

What are the solutions to the equation (r^2+1)^4=0 ?
The solutions to the equation (r^2+1)^4=0 are r=i,r=-i
Find the zeros of (r^2+1)^4=0
The zeros of (r^2+1)^4=0 are r=i,r=-i