What are the solutions to the equation 2x^3+5x^2+4x+1=0 ?

The solutions to the equation 2x^3+5x^2+4x+1=0 are x=-1,x=-1/2

Find the zeros of 2x^3+5x^2+4x+1=0

The zeros of 2x^3+5x^2+4x+1=0 are x=-1,x=-1/2

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2 x^{3} + 5 x^{2} + 4 x + 1 = 0

x = - 1, x = - \frac{1}{2}

Decimal Notation

x = - 1, x = - 0.5

Solution steps

2 x^{3} + 5 x^{2} + 4 x + 1 = 0

Factor

2 x^{3} + 5 x^{2} + 4 x + 1 : (x + 1)^{2} (2 x + 1)

(x + 1)^{2} (2 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or 2 x + 1 = 0

Solve

x + 1 = 0 : x = - 1

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

The solutions are

x = - 1, x = - \frac{1}{2}

x^{4} x - 1 = 4 x + 7

- 2 x^{3} - 6 x^{2} - 6 x - 5 = 0

x^{100} - 1 = 0

x^{3} + 3 x^{2} + 0.25 x + 4 = 0

x^{4} - 6 x^{3} + 7 x^{2} - 6 x + 1 = 0

What are the solutions to the equation 2x^3+5x^2+4x+1=0 ?
The solutions to the equation 2x^3+5x^2+4x+1=0 are x=-1,x=-1/2
Find the zeros of 2x^3+5x^2+4x+1=0
The zeros of 2x^3+5x^2+4x+1=0 are x=-1,x=-1/2