What are the solutions to the equation x^8+36=x-3+25 ?

The solutions to the equation x^8+36=x-3+25 are No Solution for x\in\mathbb{R}

Find the zeros of x^8+36=x-3+25

The zeros of x^8+36=x-3+25 are No Solution for x\in\mathbb{R}

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x^{8} + 36 = x - 3 + 25

No Solution for x \in R

Solution steps

x^{8} + 36 = x - 3 + 25

Refine

x^{8} + 36 = x + 22

Move

22

to the left side

x^{8} + 14 = x

Move

x

to the left side

x^{8} + 14 - x = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

x^{8} - x + 14 = 0

Find one solution for

x^{8} - x + 14 = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

No Solution for x \in R

m, L = 12 m^{3}

x^{3} 2 x^{2} - 11 x - 12 = 0

- x^{3} + 54 x^{2} - 6 x + 25 = 0

x^{5} + 5 x^{4} + 3 x^{2} + x + 6 = 0

\frac{x ^{5}}{3} = 1 0^{6}

What are the solutions to the equation x^8+36=x-3+25 ?
The solutions to the equation x^8+36=x-3+25 are No Solution for x\in\mathbb{R}
Find the zeros of x^8+36=x-3+25
The zeros of x^8+36=x-3+25 are No Solution for x\in\mathbb{R}