What are the solutions to the equation r^3-3r^2-r+3=0 ?

The solutions to the equation r^3-3r^2-r+3=0 are r=3,r=-1,r=1

Find the zeros of r^3-3r^2-r+3=0

The zeros of r^3-3r^2-r+3=0 are r=3,r=-1,r=1

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r^{3} - 3 r^{2} - r + 3 = 0

r = 3, r = - 1, r = 1

Solution steps

r^{3} - 3 r^{2} - r + 3 = 0

Factor

r^{3} - 3 r^{2} - r + 3 : (r - 3) (r + 1) (r - 1)

(r - 3) (r + 1) (r - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

r - 3 = 0 or r + 1 = 0 or r - 1 = 0

Solve

r - 3 = 0 : r = 3

Solve

r + 1 = 0 : r = - 1

Solve

r - 1 = 0 : r = 1

The solutions are

r = 3, r = - 1, r = 1

x^{4} - \frac{17}{4} x^{2} + 1 = 0

x^{6} - 10 x^{3} + 21 = 0

x^{3} + 6 x + 12 = 0

(x^{2} - 9) (x^{2} - 4) = 0

- 49 x^{4} + 9 x^{2} = 0

What are the solutions to the equation r^3-3r^2-r+3=0 ?
The solutions to the equation r^3-3r^2-r+3=0 are r=3,r=-1,r=1
Find the zeros of r^3-3r^2-r+3=0
The zeros of r^3-3r^2-r+3=0 are r=3,r=-1,r=1