What are the solutions to the equation 84=x^2+8x ?

The solutions to the equation 84=x^2+8x are x=6,x=-14

Find the zeros of 84=x^2+8x

The zeros of 84=x^2+8x are x=6,x=-14

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84 = x^{2} + 8 x

x = 6, x = - 14

Solution steps

84 = x^{2} + 8 x

Switch sides

x^{2} + 8 x = 84

Move

84

to the left side

x^{2} + 8 x - 84 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 84 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 84) = 20

x_{1, 2} = \frac{- 8 \pm 20}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 20}{2 \cdot 1}, x_{2} = \frac{- 8 - 20}{2 \cdot 1}

x = \frac{- 8 + 20}{2 \cdot 1} : 6

x = \frac{- 8 - 20}{2 \cdot 1} : - 14

The solutions to the quadratic equation are:

x = 6, x = - 14

6 x^{2} + x - 2

\frac{16}{3} + 5

ln (\frac{1}{e ^{8}})

\frac{1}{4} x^{2} = 1

\frac{x}{y ^{- 2}}

What are the solutions to the equation 84=x^2+8x ?
The solutions to the equation 84=x^2+8x are x=6,x=-14
Find the zeros of 84=x^2+8x
The zeros of 84=x^2+8x are x=6,x=-14