What are the solutions to the equation 2x^3+4x^2-18x-36=0 ?

The solutions to the equation 2x^3+4x^2-18x-36=0 are x=-2,x=-3,x=3

Find the zeros of 2x^3+4x^2-18x-36=0

The zeros of 2x^3+4x^2-18x-36=0 are x=-2,x=-3,x=3

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2 x^{3} + 4 x^{2} - 18 x - 36 = 0

x = - 2, x = - 3, x = 3

Solution steps

2 x^{3} + 4 x^{2} - 18 x - 36 = 0

Factor

2 x^{3} + 4 x^{2} - 18 x - 36 : 2 (x + 2) (x + 3) (x - 3)

2 (x + 2) (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x + 3 = 0 or x - 3 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = - 2, x = - 3, x = 3

(3 x - 6) - 15 x = 4 x^{6} x

x^{12} = 832

y^{3} + 3 y^{2} = 81 y + 243

(x + 1)^{3} - (x - 1) = 6 x (x - 3)

x^{3} - 7 x - 8 = 0

What are the solutions to the equation 2x^3+4x^2-18x-36=0 ?
The solutions to the equation 2x^3+4x^2-18x-36=0 are x=-2,x=-3,x=3
Find the zeros of 2x^3+4x^2-18x-36=0
The zeros of 2x^3+4x^2-18x-36=0 are x=-2,x=-3,x=3