What are the solutions to the equation (32x^7)/(253125)=x^3 ?

The solutions to the equation (32x^7)/(253125)=x^3 are

Find the zeros of (32x^7)/(253125)=x^3

The zeros of (32x^7)/(253125)=x^3 are

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\frac{32 x ^{7}}{253125} = x^{3}

Solution steps

\frac{32 x ^{7}}{253125} = x^{3}

Move

x^{3}

to the left side

\frac{32 x ^{7}}{253125} - x^{3} = 0

Factor

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

\frac{4 2 x ^{2}}{225 5} + 1 = 0 : x = - \frac{225 5}{4 2}, x = - - \frac{225 5}{4 2}

Solve

The solutions are

2 m^{3} - 34 m^{2} + 144 m = 0

e^{9} e + 4 = - 5 e + 14 + 13 e

x^{3} + 14 x^{2} + 56 x + 64 = 0

80 z^{4} - 4 z^{3} - 6 z^{2} - 4 z - 1 = 0

9 (x + 2)^{4} + 17 (x + 2)^{2} - 2 = 0

What are the solutions to the equation (32x^7)/(253125)=x^3 ?
The solutions to the equation (32x^7)/(253125)=x^3 are
Find the zeros of (32x^7)/(253125)=x^3
The zeros of (32x^7)/(253125)=x^3 are