What are the solutions to the equation b^3-b^2-b+1=0 ?

The solutions to the equation b^3-b^2-b+1=0 are b=1,b=-1

Find the zeros of b^3-b^2-b+1=0

The zeros of b^3-b^2-b+1=0 are b=1,b=-1

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b^{3} - b^{2} - b + 1 = 0

b = 1, b = - 1

Solution steps

b^{3} - b^{2} - b + 1 = 0

Factor

b^{3} - b^{2} - b + 1 : (b - 1)^{2} (b + 1)

(b - 1)^{2} (b + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

b - 1 = 0 or b + 1 = 0

Solve

b - 1 = 0 : b = 1

Solve

b + 1 = 0 : b = - 1

The solutions are

b = 1, b = - 1

x^{4} - x^{6} = 5

3 x + 2 = 2 x^{4}

3 x^{3} + 12 x^{2} - 9 x - 15 = 0

x^{3} - 4 x^{2} - 29 x - 24 = 0

a^{3} + a^{2} - 3 = 0

What are the solutions to the equation b^3-b^2-b+1=0 ?
The solutions to the equation b^3-b^2-b+1=0 are b=1,b=-1
Find the zeros of b^3-b^2-b+1=0
The zeros of b^3-b^2-b+1=0 are b=1,b=-1