What are the solutions to the equation 0=-x^3-3x^2+54x ?

The solutions to the equation 0=-x^3-3x^2+54x are x=0,x=6,x=-9

Find the zeros of 0=-x^3-3x^2+54x

The zeros of 0=-x^3-3x^2+54x are x=0,x=6,x=-9

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0 = - x^{3} - 3 x^{2} + 54 x

x = 0, x = 6, x = - 9

Solution steps

0 = - x^{3} - 3 x^{2} + 54 x

Switch sides

- x^{3} - 3 x^{2} + 54 x = 0

Factor

- x^{3} - 3 x^{2} + 54 x : - x (x - 6) (x + 9)

- x (x - 6) (x + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 6 = 0 or x + 9 = 0

Solve

x - 6 = 0 : x = 6

Solve

x + 9 = 0 : x = - 9

The solutions are

x = 0, x = 6, x = - 9

x^{3} + 7 x - 6 = 0

- 6 + x^{3} = 0

x^{4} - 2 x^{3} - 3 x^{2} + 4 x + 4 = 64 x + 4

(5 x - 2) (3 x^{2} - 12) (x^{2} + 3 x) = 0

4 t^{3} - 12 t^{2} - 40 t + 20 = 20

What are the solutions to the equation 0=-x^3-3x^2+54x ?
The solutions to the equation 0=-x^3-3x^2+54x are x=0,x=6,x=-9
Find the zeros of 0=-x^3-3x^2+54x
The zeros of 0=-x^3-3x^2+54x are x=0,x=6,x=-9