What are the solutions to the equation 32x^5-162x=0 ?

The solutions to the equation 32x^5-162x=0 are x=0,x= 3/2 i,x=-3/2 i,x=-3/2 ,x= 3/2

Find the zeros of 32x^5-162x=0

The zeros of 32x^5-162x=0 are x=0,x= 3/2 i,x=-3/2 i,x=-3/2 ,x= 3/2

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32 x^{5} - 162 x = 0

x = 0, x = \frac{3}{2} i, x = - \frac{3}{2} i, x = - \frac{3}{2}, x = \frac{3}{2}

Solution steps

32 x^{5} - 162 x = 0

Factor

32 x^{5} - 162 x : 2 x (4 x^{2} + 9) (2 x + 3) (2 x - 3)

2 x (4 x^{2} + 9) (2 x + 3) (2 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 4 x^{2} + 9 = 0 or 2 x + 3 = 0 or 2 x - 3 = 0

Solve

4 x^{2} + 9 = 0 : x = \frac{3}{2} i, x = - \frac{3}{2} i

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

2 x - 3 = 0 : x = \frac{3}{2}

The solutions are

x = 0, x = \frac{3}{2} i, x = - \frac{3}{2} i, x = - \frac{3}{2}, x = \frac{3}{2}

x^{3} - 3 x^{2} - x + 1 = 0

k^{3} = 5

y^{4} - 3 y^{2} + 2 = 0

x^{4} = 13 x^{2} - 36

0 = 6 x^{2} + 4 x^{3}

What are the solutions to the equation 32x^5-162x=0 ?
The solutions to the equation 32x^5-162x=0 are x=0,x= 3/2 i,x=-3/2 i,x=-3/2 ,x= 3/2
Find the zeros of 32x^5-162x=0
The zeros of 32x^5-162x=0 are x=0,x= 3/2 i,x=-3/2 i,x=-3/2 ,x= 3/2