What are the solutions to the equation -x^3+7x^2+17x+9=0 ?

The solutions to the equation -x^3+7x^2+17x+9=0 are x=-1,x=9

Find the zeros of -x^3+7x^2+17x+9=0

The zeros of -x^3+7x^2+17x+9=0 are x=-1,x=9

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- x^{3} + 7 x^{2} + 17 x + 9 = 0

x = - 1, x = 9

Solution steps

- x^{3} + 7 x^{2} + 17 x + 9 = 0

Factor

- x^{3} + 7 x^{2} + 17 x + 9 : - (x + 1)^{2} (x - 9)

- (x + 1)^{2} (x - 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 9 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 9 = 0 : x = 9

The solutions are

x = - 1, x = 9

- 3 x^{10} = 5 x - 8

(2 n + 2) (n + 1) (n + 2) = 160

x^{4} - 12 x^{2} = - 32

1200 = 600 \cdot (1 + x)^{10}

r^{3} + 3 r^{2} - 4 = 0

What are the solutions to the equation -x^3+7x^2+17x+9=0 ?
The solutions to the equation -x^3+7x^2+17x+9=0 are x=-1,x=9
Find the zeros of -x^3+7x^2+17x+9=0
The zeros of -x^3+7x^2+17x+9=0 are x=-1,x=9