What are the solutions to the equation x^3+(5x^2)/2+4x=0 ?

The solutions to the equation x^3+(5x^2)/2+4x=0 are x=0,x=-5/4+i(sqrt(39))/4 ,x=-5/4-i(sqrt(39))/4

Find the zeros of x^3+(5x^2)/2+4x=0

The zeros of x^3+(5x^2)/2+4x=0 are x=0,x=-5/4+i(sqrt(39))/4 ,x=-5/4-i(sqrt(39))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{3} + \frac{5 x ^{2}}{2} + 4 x = 0

x = 0, x = - \frac{5}{4} + i \frac{39}{4}, x = - \frac{5}{4} - i \frac{39}{4}

Solution steps

x^{3} + \frac{5 x ^{2}}{2} + 4 x = 0

Factor

x^{3} + \frac{5 x ^{2}}{2} + 4 x : x (x^{2} + \frac{5 x}{2} + 4)

x (x^{2} + \frac{5 x}{2} + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} + \frac{5 x}{2} + 4 = 0

Solve

x^{2} + \frac{5 x}{2} + 4 = 0 : x = - \frac{5}{4} + i \frac{39}{4}, x = - \frac{5}{4} - i \frac{39}{4}

The solutions are

x = 0, x = - \frac{5}{4} + i \frac{39}{4}, x = - \frac{5}{4} - i \frac{39}{4}

b^{3} = 3

0 = 4 x^{3}

6 x^{3} - 11 x^{2} + 6 x - 1 = 0

2 x^{3} - x^{2} - 2 x - 1 = 0

2 x (4 - 2) = 4 + x^{8}

What are the solutions to the equation x^3+(5x^2)/2+4x=0 ?
The solutions to the equation x^3+(5x^2)/2+4x=0 are x=0,x=-5/4+i(sqrt(39))/4 ,x=-5/4-i(sqrt(39))/4
Find the zeros of x^3+(5x^2)/2+4x=0
The zeros of x^3+(5x^2)/2+4x=0 are x=0,x=-5/4+i(sqrt(39))/4 ,x=-5/4-i(sqrt(39))/4