What are the solutions to the equation 2y^3-5y^2-3y=0 ?

The solutions to the equation 2y^3-5y^2-3y=0 are y=0,y=-1/2 ,y=3

Find the zeros of 2y^3-5y^2-3y=0

The zeros of 2y^3-5y^2-3y=0 are y=0,y=-1/2 ,y=3

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2 y^{3} - 5 y^{2} - 3 y = 0

y = 0, y = - \frac{1}{2}, y = 3

Decimal Notation

y = 0, y = - 0.5, y = 3

Solution steps

2 y^{3} - 5 y^{2} - 3 y = 0

Factor

2 y^{3} - 5 y^{2} - 3 y : y (2 y + 1) (y - 3)

y (2 y + 1) (y - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or 2 y + 1 = 0 or y - 3 = 0

Solve

2 y + 1 = 0 : y = - \frac{1}{2}

Solve

y - 3 = 0 : y = 3

The solutions are

y = 0, y = - \frac{1}{2}, y = 3

6 x^{3} - 12 = 0

2 - x + x^{3} = 0

r^{3} = \frac{1}{7 ^{3}}

x^{3} - 27 x = 0

z^{6} - 12 = 0

What are the solutions to the equation 2y^3-5y^2-3y=0 ?
The solutions to the equation 2y^3-5y^2-3y=0 are y=0,y=-1/2 ,y=3
Find the zeros of 2y^3-5y^2-3y=0
The zeros of 2y^3-5y^2-3y=0 are y=0,y=-1/2 ,y=3