What are the solutions to the equation 81x^2-54x+9=0 ?

The solutions to the equation 81x^2-54x+9=0 are x= 1/3

Find the zeros of 81x^2-54x+9=0

The zeros of 81x^2-54x+9=0 are x= 1/3

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81 x^{2} - 54 x + 9 = 0

x = \frac{1}{3}

Decimal Notation

x = 0.33333 \dots

Solution steps

81 x^{2} - 54 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 54 ) \pm ( - 54 ) ^{2} - 4 \cdot 81 \cdot 9}{2 \cdot 81}

(- 54)^{2} - 4 \cdot 81 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 54 ) \pm 0}{2 \cdot 81}

x = \frac{- ( - 54 )}{2 \cdot 81}

\frac{- ( - 54 )}{2 \cdot 81} = \frac{1}{3}

x = \frac{1}{3}

The solution to the quadratic equation is:

x = \frac{1}{3}

2 x^{2} + 5 x + 2 \geq 0

(35 - 23 i) + (13 + 25 i)

a^{2} y^{2} + 14 a y - 240

\frac{f}{4} + 6 = 16

\frac{x}{3} - \frac{1}{12} \leq \frac{x}{4} + 1

What are the solutions to the equation 81x^2-54x+9=0 ?
The solutions to the equation 81x^2-54x+9=0 are x= 1/3
Find the zeros of 81x^2-54x+9=0
The zeros of 81x^2-54x+9=0 are x= 1/3