What are the solutions to the equation x^4+2x^3-11x^2-12x+36=0 ?

The solutions to the equation x^4+2x^3-11x^2-12x+36=0 are x=2,x=-3

Find the zeros of x^4+2x^3-11x^2-12x+36=0

The zeros of x^4+2x^3-11x^2-12x+36=0 are x=2,x=-3

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x^{4} + 2 x^{3} - 11 x^{2} - 12 x + 36 = 0

x = 2, x = - 3

Solution steps

x^{4} + 2 x^{3} - 11 x^{2} - 12 x + 36 = 0

Factor

x^{4} + 2 x^{3} - 11 x^{2} - 12 x + 36 : (x - 2)^{2} (x + 3)^{2}

(x - 2)^{2} (x + 3)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x + 3 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 3 = 0 : x = - 3

The solutions are

x = 2, x = - 3

x^{2} + x^{10} = 0

4 \cdot x^{3} = 32

x, x x^{2} + y^{2} = 0

x^{3} - 7 x^{2} + 2 x + 40 = 0

r^{3} = 6

What are the solutions to the equation x^4+2x^3-11x^2-12x+36=0 ?
The solutions to the equation x^4+2x^3-11x^2-12x+36=0 are x=2,x=-3
Find the zeros of x^4+2x^3-11x^2-12x+36=0
The zeros of x^4+2x^3-11x^2-12x+36=0 are x=2,x=-3